Optimal. Leaf size=209 \[ -\frac{2 a^2 \cos ^{11}(c+d x)}{11 d}+\frac{4 a^2 \cos ^9(c+d x)}{9 d}-\frac{2 a^2 \cos ^7(c+d x)}{7 d}-\frac{a^2 \sin ^5(c+d x) \cos ^7(c+d x)}{12 d}-\frac{17 a^2 \sin ^3(c+d x) \cos ^7(c+d x)}{120 d}-\frac{17 a^2 \sin (c+d x) \cos ^7(c+d x)}{320 d}+\frac{17 a^2 \sin (c+d x) \cos ^5(c+d x)}{1920 d}+\frac{17 a^2 \sin (c+d x) \cos ^3(c+d x)}{1536 d}+\frac{17 a^2 \sin (c+d x) \cos (c+d x)}{1024 d}+\frac{17 a^2 x}{1024} \]
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Rubi [A] time = 0.395716, antiderivative size = 209, normalized size of antiderivative = 1., number of steps used = 18, number of rules used = 6, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.207, Rules used = {2873, 2568, 2635, 8, 2565, 270} \[ -\frac{2 a^2 \cos ^{11}(c+d x)}{11 d}+\frac{4 a^2 \cos ^9(c+d x)}{9 d}-\frac{2 a^2 \cos ^7(c+d x)}{7 d}-\frac{a^2 \sin ^5(c+d x) \cos ^7(c+d x)}{12 d}-\frac{17 a^2 \sin ^3(c+d x) \cos ^7(c+d x)}{120 d}-\frac{17 a^2 \sin (c+d x) \cos ^7(c+d x)}{320 d}+\frac{17 a^2 \sin (c+d x) \cos ^5(c+d x)}{1920 d}+\frac{17 a^2 \sin (c+d x) \cos ^3(c+d x)}{1536 d}+\frac{17 a^2 \sin (c+d x) \cos (c+d x)}{1024 d}+\frac{17 a^2 x}{1024} \]
Antiderivative was successfully verified.
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Rule 2873
Rule 2568
Rule 2635
Rule 8
Rule 2565
Rule 270
Rubi steps
\begin{align*} \int \cos ^6(c+d x) \sin ^4(c+d x) (a+a \sin (c+d x))^2 \, dx &=\int \left (a^2 \cos ^6(c+d x) \sin ^4(c+d x)+2 a^2 \cos ^6(c+d x) \sin ^5(c+d x)+a^2 \cos ^6(c+d x) \sin ^6(c+d x)\right ) \, dx\\ &=a^2 \int \cos ^6(c+d x) \sin ^4(c+d x) \, dx+a^2 \int \cos ^6(c+d x) \sin ^6(c+d x) \, dx+\left (2 a^2\right ) \int \cos ^6(c+d x) \sin ^5(c+d x) \, dx\\ &=-\frac{a^2 \cos ^7(c+d x) \sin ^3(c+d x)}{10 d}-\frac{a^2 \cos ^7(c+d x) \sin ^5(c+d x)}{12 d}+\frac{1}{10} \left (3 a^2\right ) \int \cos ^6(c+d x) \sin ^2(c+d x) \, dx+\frac{1}{12} \left (5 a^2\right ) \int \cos ^6(c+d x) \sin ^4(c+d x) \, dx-\frac{\left (2 a^2\right ) \operatorname{Subst}\left (\int x^6 \left (1-x^2\right )^2 \, dx,x,\cos (c+d x)\right )}{d}\\ &=-\frac{3 a^2 \cos ^7(c+d x) \sin (c+d x)}{80 d}-\frac{17 a^2 \cos ^7(c+d x) \sin ^3(c+d x)}{120 d}-\frac{a^2 \cos ^7(c+d x) \sin ^5(c+d x)}{12 d}+\frac{1}{80} \left (3 a^2\right ) \int \cos ^6(c+d x) \, dx+\frac{1}{8} a^2 \int \cos ^6(c+d x) \sin ^2(c+d x) \, dx-\frac{\left (2 a^2\right ) \operatorname{Subst}\left (\int \left (x^6-2 x^8+x^{10}\right ) \, dx,x,\cos (c+d x)\right )}{d}\\ &=-\frac{2 a^2 \cos ^7(c+d x)}{7 d}+\frac{4 a^2 \cos ^9(c+d x)}{9 d}-\frac{2 a^2 \cos ^{11}(c+d x)}{11 d}+\frac{a^2 \cos ^5(c+d x) \sin (c+d x)}{160 d}-\frac{17 a^2 \cos ^7(c+d x) \sin (c+d x)}{320 d}-\frac{17 a^2 \cos ^7(c+d x) \sin ^3(c+d x)}{120 d}-\frac{a^2 \cos ^7(c+d x) \sin ^5(c+d x)}{12 d}+\frac{1}{64} a^2 \int \cos ^6(c+d x) \, dx+\frac{1}{32} a^2 \int \cos ^4(c+d x) \, dx\\ &=-\frac{2 a^2 \cos ^7(c+d x)}{7 d}+\frac{4 a^2 \cos ^9(c+d x)}{9 d}-\frac{2 a^2 \cos ^{11}(c+d x)}{11 d}+\frac{a^2 \cos ^3(c+d x) \sin (c+d x)}{128 d}+\frac{17 a^2 \cos ^5(c+d x) \sin (c+d x)}{1920 d}-\frac{17 a^2 \cos ^7(c+d x) \sin (c+d x)}{320 d}-\frac{17 a^2 \cos ^7(c+d x) \sin ^3(c+d x)}{120 d}-\frac{a^2 \cos ^7(c+d x) \sin ^5(c+d x)}{12 d}+\frac{1}{384} \left (5 a^2\right ) \int \cos ^4(c+d x) \, dx+\frac{1}{128} \left (3 a^2\right ) \int \cos ^2(c+d x) \, dx\\ &=-\frac{2 a^2 \cos ^7(c+d x)}{7 d}+\frac{4 a^2 \cos ^9(c+d x)}{9 d}-\frac{2 a^2 \cos ^{11}(c+d x)}{11 d}+\frac{3 a^2 \cos (c+d x) \sin (c+d x)}{256 d}+\frac{17 a^2 \cos ^3(c+d x) \sin (c+d x)}{1536 d}+\frac{17 a^2 \cos ^5(c+d x) \sin (c+d x)}{1920 d}-\frac{17 a^2 \cos ^7(c+d x) \sin (c+d x)}{320 d}-\frac{17 a^2 \cos ^7(c+d x) \sin ^3(c+d x)}{120 d}-\frac{a^2 \cos ^7(c+d x) \sin ^5(c+d x)}{12 d}+\frac{1}{512} \left (5 a^2\right ) \int \cos ^2(c+d x) \, dx+\frac{1}{256} \left (3 a^2\right ) \int 1 \, dx\\ &=\frac{3 a^2 x}{256}-\frac{2 a^2 \cos ^7(c+d x)}{7 d}+\frac{4 a^2 \cos ^9(c+d x)}{9 d}-\frac{2 a^2 \cos ^{11}(c+d x)}{11 d}+\frac{17 a^2 \cos (c+d x) \sin (c+d x)}{1024 d}+\frac{17 a^2 \cos ^3(c+d x) \sin (c+d x)}{1536 d}+\frac{17 a^2 \cos ^5(c+d x) \sin (c+d x)}{1920 d}-\frac{17 a^2 \cos ^7(c+d x) \sin (c+d x)}{320 d}-\frac{17 a^2 \cos ^7(c+d x) \sin ^3(c+d x)}{120 d}-\frac{a^2 \cos ^7(c+d x) \sin ^5(c+d x)}{12 d}+\frac{\left (5 a^2\right ) \int 1 \, dx}{1024}\\ &=\frac{17 a^2 x}{1024}-\frac{2 a^2 \cos ^7(c+d x)}{7 d}+\frac{4 a^2 \cos ^9(c+d x)}{9 d}-\frac{2 a^2 \cos ^{11}(c+d x)}{11 d}+\frac{17 a^2 \cos (c+d x) \sin (c+d x)}{1024 d}+\frac{17 a^2 \cos ^3(c+d x) \sin (c+d x)}{1536 d}+\frac{17 a^2 \cos ^5(c+d x) \sin (c+d x)}{1920 d}-\frac{17 a^2 \cos ^7(c+d x) \sin (c+d x)}{320 d}-\frac{17 a^2 \cos ^7(c+d x) \sin ^3(c+d x)}{120 d}-\frac{a^2 \cos ^7(c+d x) \sin ^5(c+d x)}{12 d}\\ \end{align*}
Mathematica [A] time = 1.34498, size = 136, normalized size = 0.65 \[ \frac{a^2 (55440 \sin (2 (c+d x))-162855 \sin (4 (c+d x))-27720 \sin (6 (c+d x))+24255 \sin (8 (c+d x))+5544 \sin (10 (c+d x))-1155 \sin (12 (c+d x))-554400 \cos (c+d x)-184800 \cos (3 (c+d x))+55440 \cos (5 (c+d x))+39600 \cos (7 (c+d x))-6160 \cos (9 (c+d x))-5040 \cos (11 (c+d x))+166320 c+471240 d x)}{28385280 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.04, size = 238, normalized size = 1.1 \begin{align*}{\frac{1}{d} \left ({a}^{2} \left ( -{\frac{ \left ( \sin \left ( dx+c \right ) \right ) ^{5} \left ( \cos \left ( dx+c \right ) \right ) ^{7}}{12}}-{\frac{ \left ( \sin \left ( dx+c \right ) \right ) ^{3} \left ( \cos \left ( dx+c \right ) \right ) ^{7}}{24}}-{\frac{\sin \left ( dx+c \right ) \left ( \cos \left ( dx+c \right ) \right ) ^{7}}{64}}+{\frac{\sin \left ( dx+c \right ) }{384} \left ( \left ( \cos \left ( dx+c \right ) \right ) ^{5}+{\frac{5\, \left ( \cos \left ( dx+c \right ) \right ) ^{3}}{4}}+{\frac{15\,\cos \left ( dx+c \right ) }{8}} \right ) }+{\frac{5\,dx}{1024}}+{\frac{5\,c}{1024}} \right ) +2\,{a}^{2} \left ( -1/11\, \left ( \sin \left ( dx+c \right ) \right ) ^{4} \left ( \cos \left ( dx+c \right ) \right ) ^{7}-{\frac{4\, \left ( \sin \left ( dx+c \right ) \right ) ^{2} \left ( \cos \left ( dx+c \right ) \right ) ^{7}}{99}}-{\frac{8\, \left ( \cos \left ( dx+c \right ) \right ) ^{7}}{693}} \right ) +{a}^{2} \left ( -{\frac{ \left ( \sin \left ( dx+c \right ) \right ) ^{3} \left ( \cos \left ( dx+c \right ) \right ) ^{7}}{10}}-{\frac{3\,\sin \left ( dx+c \right ) \left ( \cos \left ( dx+c \right ) \right ) ^{7}}{80}}+{\frac{\sin \left ( dx+c \right ) }{160} \left ( \left ( \cos \left ( dx+c \right ) \right ) ^{5}+{\frac{5\, \left ( \cos \left ( dx+c \right ) \right ) ^{3}}{4}}+{\frac{15\,\cos \left ( dx+c \right ) }{8}} \right ) }+{\frac{3\,dx}{256}}+{\frac{3\,c}{256}} \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.04498, size = 186, normalized size = 0.89 \begin{align*} -\frac{81920 \,{\left (63 \, \cos \left (d x + c\right )^{11} - 154 \, \cos \left (d x + c\right )^{9} + 99 \, \cos \left (d x + c\right )^{7}\right )} a^{2} - 2772 \,{\left (32 \, \sin \left (2 \, d x + 2 \, c\right )^{5} + 120 \, d x + 120 \, c + 5 \, \sin \left (8 \, d x + 8 \, c\right ) - 40 \, \sin \left (4 \, d x + 4 \, c\right )\right )} a^{2} - 1155 \,{\left (4 \, \sin \left (4 \, d x + 4 \, c\right )^{3} + 120 \, d x + 120 \, c + 9 \, \sin \left (8 \, d x + 8 \, c\right ) - 48 \, \sin \left (4 \, d x + 4 \, c\right )\right )} a^{2}}{28385280 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.28049, size = 389, normalized size = 1.86 \begin{align*} -\frac{645120 \, a^{2} \cos \left (d x + c\right )^{11} - 1576960 \, a^{2} \cos \left (d x + c\right )^{9} + 1013760 \, a^{2} \cos \left (d x + c\right )^{7} - 58905 \, a^{2} d x + 231 \,{\left (1280 \, a^{2} \cos \left (d x + c\right )^{11} - 4736 \, a^{2} \cos \left (d x + c\right )^{9} + 4272 \, a^{2} \cos \left (d x + c\right )^{7} - 136 \, a^{2} \cos \left (d x + c\right )^{5} - 170 \, a^{2} \cos \left (d x + c\right )^{3} - 255 \, a^{2} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{3548160 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 89.7845, size = 656, normalized size = 3.14 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.25871, size = 281, normalized size = 1.34 \begin{align*} \frac{17}{1024} \, a^{2} x - \frac{a^{2} \cos \left (11 \, d x + 11 \, c\right )}{5632 \, d} - \frac{a^{2} \cos \left (9 \, d x + 9 \, c\right )}{4608 \, d} + \frac{5 \, a^{2} \cos \left (7 \, d x + 7 \, c\right )}{3584 \, d} + \frac{a^{2} \cos \left (5 \, d x + 5 \, c\right )}{512 \, d} - \frac{5 \, a^{2} \cos \left (3 \, d x + 3 \, c\right )}{768 \, d} - \frac{5 \, a^{2} \cos \left (d x + c\right )}{256 \, d} - \frac{a^{2} \sin \left (12 \, d x + 12 \, c\right )}{24576 \, d} + \frac{a^{2} \sin \left (10 \, d x + 10 \, c\right )}{5120 \, d} + \frac{7 \, a^{2} \sin \left (8 \, d x + 8 \, c\right )}{8192 \, d} - \frac{a^{2} \sin \left (6 \, d x + 6 \, c\right )}{1024 \, d} - \frac{47 \, a^{2} \sin \left (4 \, d x + 4 \, c\right )}{8192 \, d} + \frac{a^{2} \sin \left (2 \, d x + 2 \, c\right )}{512 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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